2013-07-03

Rate Law and Integrated Rate Law Problem {2013-07-03}

Under some set of conditions, ammonia gas and fluorine gas react to form nitrogen trifluoride gas and hydrogen gas at 8.73ºC. What is the correct rate law expression (including the rate law constant) given the following data:
Rxn #
[NH3]0
[F2]0
Rate (M/min)
1
0.274
0.218
1.841x10-2
2
0.274
0.436
7.362x10-2
3
0.822
0.436
2.209x10-1
The rate law expression for this reaction is:
Rate0 = k[NH3]0x [F2]0y
Comparing Rxn #1 and #2:
y = 2, the reaction is 2nd order with respect to fluorine concentration
Comparing Rxn #3 and #2:
x = 1, the reaction is 1st order w.r.t. ammonia concentration
Plugging in values from Rxn #1 and solving for k...
1.841x10-2 M/min = k (0.274M)1 (0.218M)2
k = 1.42 M-2min-1

In Rxn #2, how much time must pass before [F2] = 0.324M?
Plugging in to the 2nd order integrated rate law expression...
t = 0.558 minutes

In Rxn #1, how much time must pass before [NH3] = 0.217M?
Plugging in to the 1st order integrated rate law expression...
t = 0.164 minutes


2 comments:

  1. I was wondering if what we learned today (July 15) is going to be part of our exam tomorrow. Thank you!

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  2. The material that was specifically acids & bases, no. BUT we talked about a lot of equilibrium in class today, and your exam is on equilibrium, so some of the concepts we talked about today might be related to material on the exam. Good luck.

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